3[9(9x+1)]=81x+36

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Solution for 3[9(9x+1)]=81x+36 equation:


Simplifying
3[9(9x + 1)] = 81x + 36

Reorder the terms:
3[9(1 + 9x)] = 81x + 36
3[(1 * 9 + 9x * 9)] = 81x + 36
3[(9 + 81x)] = 81x + 36
[9 * 3 + 81x * 3] = 81x + 36
[27 + 243x] = 81x + 36

Reorder the terms:
27 + 243x = 36 + 81x

Solving
27 + 243x = 36 + 81x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-81x' to each side of the equation.
27 + 243x + -81x = 36 + 81x + -81x

Combine like terms: 243x + -81x = 162x
27 + 162x = 36 + 81x + -81x

Combine like terms: 81x + -81x = 0
27 + 162x = 36 + 0
27 + 162x = 36

Add '-27' to each side of the equation.
27 + -27 + 162x = 36 + -27

Combine like terms: 27 + -27 = 0
0 + 162x = 36 + -27
162x = 36 + -27

Combine like terms: 36 + -27 = 9
162x = 9

Divide each side by '162'.
x = 0.05555555556

Simplifying
x = 0.05555555556

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